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NEW QUESTION: 1
What is the default HSRP priority?
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
Explanation/Reference:
Explanation:
standby [group-num- Set a priority value used in choosing the active router. The ber] priority priority range is 1 to 255; the default priority is 100. The highest [preempt [delay delay]] number represents the highest priority.
(Optional) group-number--The group number to which

the command applies.
(Optional) preempt--Select so that when the local router has a higher priority than the active router, it

assumes control as the active router.
(Optional) delay--Set to cause the local router to post- pone taking over the active role for the shown

number of sec- onds. The range is 0 to 36000 (1 hour); the default is 0 (no de- lay before taking over).
Use the no form of the command to restore the default values.
Reference:
http://www.cisco.com/en/US/docs/switches/lan/catalyst3550/software/release/12.1_19_ea1/confi guration/ guide/swhsrp.html#wp1044327

NEW QUESTION: 2
Which of the following is not described in a unit test standard?
A. equivalence partitioning
B. syntax testing
C. decision coverage
D. stress testing
Answer: D

NEW QUESTION: 3
View the Exhibit and examine the description for the CUSTOMERS table.

You want to update the CUST_INCOME_LEVEL and CUST_CREDIT_LIMIT columns for the customer with the CUST_ID 2360. You want the value for the CUST_INCOME_LEVEL to have the same value as that of the customer with the CUST_ID 2560 and the CUST_CREDIT_LIMIT to have the same value as that of the customer with CUST_ID 2566.
Which UPDATE statement will accomplish the task?
A. UPDATE customers SET (cust_income_level,cust_credit_limit) = (SELECT cust_income_level, cust_credit_limit FROM customers WHERE cust_id=2560 AND cust_id=2566) WHERE cust_id=2360;
B. UPDATE customers SET (cust_income_level,cust_credit_limit) = (SELECT cust_income_level, cust_credit_limit
FROM customers
WHERE cust_id IN(2560, 2566)
WHERE cust_id=2360;
C. UPDATE customers SET cust_income_level = (SELECT cust_income_level FROM customers WHERE cust_id = 2560), cust_credit_limit = (SELECT cust_credit_limit FROM customers WHERE cust_id = 2566) WHERE cust_id=2360;
D. UPDATE customers SET (cust_income_level,cust_credit_limit) = (SELECT cust_income_level, cust_credit_limit FROM customers WHERE cust_id=2560 OR cust_id=2566) WHERE cust_id=2360;
Answer: C
Explanation:
Updating Two Columns with a Subquery
You can update multiple columns in the SET clause of an UPDATE statement by writing
multiple subqueries. The syntax is as follows:
UPDATE table
SET column =
(SELECT column
FROM table
WHERE condition)
[ ,
column =
(SELECT column
FROM table
WHERE condition)]
[WHERE condition ] ;

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