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NEW QUESTION: 1
You want to display OTBI reports and graphs in PowerPoint to show general ledger or subledger data.
How do you accomplish this?
A. Download OTBI reports and charts to a spreadsheet and then copy and paste the spreadsheet to PowerPoint
B. Use Smart View and Oracle BI EE View Designer to create reports in PowerPoint,Word,and Excel.
C. Use SmartView to create reports and charts using general ledger and subledger subject areas embed the charts/reports into PowerPoint
D. Use Account Inspector and then export to Excel and copy and paste into PowerPoint.
Answer: B
Explanation:
Reference:
http://www.oracle.com/webfolder/technetwork/tutorials/obe/fmw/bi/biee/r1013/smartview/smart_vie w.htm

NEW QUESTION: 2
実装グループは、テストベッドを使用して、クライアント1とクライアント2の両方が209.65.200.241でWEBサーバーにアクセスすることを要求する「概念実証」を行っています。
ネットワークアドレス指定、ルーティングスキーム、DHCPサービス、NTPサービス、レイヤ2接続、FHRPサービス、およびデバイスセキュリティに対するいくつかの変更を行った後、クライアント1が209.65.200.241アドレスにpingできないことを示すトラブルチケットが開かれました。
サポートされているコマンドを使用して、このフォールトの原因を特定し、次の質問に答えます。
障害状態はどのデバイスにありますか？
A. R2
B. ASW1
C. R4
D. R3
E. DSW1
F. DSW2
G. R1
H. ASW2
Answer: C
Explanation:
On R4 the DHCP IP address is not allowed for network 10.2.1.0/24 which clearly shows the problem lies on R4 & the problem is with DHCP
Topic 6, Ticket 14: IPv6 Routing Issue 1
Topology Overview
(Actual Troubleshooting lab design is for below network design)
* Client Should have IP 10.2.1.3
* EIGRP 100 is running between switch DSW1 & DSW2
* OSPF (Process ID 1) is running between R1, R2, R3, R4
* Network of OSPF is redistributed in EIGRP
* BGP 65001 is configured on R1 with Webserver cloud AS 65002
* HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside (209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution

NEW QUESTION: 3
ネットワークには、Contoso.comという名前のオンプレミスActive Directoryが含まれています。ドメインには、Microsoft Exchange Server 2019組織が含まれています。
ドメインをAzure Active Directory（Azure AD）に同期し、デバイスの書き戻しとグループの書き戻しを有効にする予定です。
Azure ADから同期するグループの種類を識別する必要があります。
どの2つのグループタイプを識別する必要がありますか？それぞれの正解はソリューションの一部を示しています。
注：それぞれの正しい選択には1ポイントの価値があります。
A. 割り当てられたメンバーシップタイプを使用するOffice 365グループ
B. ダイナミックデバイスメンバーシップタイプを使用するセキュリティグループ。
C. セキュリティグループは割り当てられたメンバーシップタイプを使用します
D. 動的ユーザーメンバーシップタイプを使用するセキュリティグループ
E. ダイナミックユーザーメンバーシップタイプを使用するOffice 365グループ
Answer: B,D

NEW QUESTION: 4

IntStream stream = IntStream.of (1,2,3); IntFunction<Integer> inFu= x -> y -> x*y;//line n1 IntStream newStream = stream.map(inFu.apply(10));//line n2
newStream.forEach(System.output::print);

A. Replace line n1 with:
BiFunction<IntUnaryOperator> inFu = x -> y -> x*y;
B. Replace line n1 with:
IntFunction<IntUnaryOperator> inFu = x -> y -> x*y;
C. Replace line n1 with:
IntFunction<UnaryOperator> inFu = x -> y -> x*y;
D. Replace line n2 with:
IntStream newStream = stream.map(inFu.applyAsInt (10));
Answer: B

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