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NEW QUESTION: 1
Click on the exhibit.

If router R2 re-distributes the IS-IS route 192.168.3.0/24 into OSPF, router R3 will receive two routes to 192.168.3.0/24 Assume that all IS-IS routers are L1/L2 capable and are in the same area.
What will be the preference of the two routes?
A. OSPF external preference and IS-IS Level 1 external preference.
B. OSPF internal preference and IS-IS Level 1 internal preference.
C. OSPF internal preference and IS-IS Level 1 external preference.
D. OSPF external preference and IS-IS Level 2 internal preference.
E. OSPF external preference and IS-IS Level 1 internal preference.
Answer: E

NEW QUESTION: 2
An IT team is designing a Proof of Concept (PoC) for a mobile email account provisioning system. Which best describes this activity?
A. A process to solicit and screen beta testers for the first release of the product.
B. A small and well defined exercise that directly measures and validates assumptions around a subset of capabilities.
C. A partially configured implementation in a non-production environment that the team can use to learn the new system and provide requirements.
D. A fully configured implementation in production that a small set of power-users use to validate how the system will be used in the field and to refine functionality.
Answer: B

NEW QUESTION: 3

A. WITH CTEDupRecords
AS
(
SELECT MIN(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
B. WITH CTEDupRecords
AS
(
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
cte.ProductName = p.ProductName
AND cte.CreatedDateTime > p.CreatedDateTime
C. WITH CTEDupRecords
AS
(
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
AND p.CreatedDateTime > cte.CreatedDateTime
D. WITH CTEDupRecords
AS
(
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
Answer: B

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