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NEW QUESTION: 1
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
B. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
C. SELECT StudentCode as Code,RANK() OVER (ORDER BY AVG (Marks) DESC) AS ValueFROM StudentMarksGROUP BY StudentCode
D. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
F. SELECT StudentCode as Code,DENSE_RANK() OVER (ORDER BY AVG (Marks)
DESC) AS ValueFROM StudentMarksGROUP BY StudentCode
G. SELECT Id, Name, Marks,DENSE_RANK() OVER (ORDER BY Marks DESC) AS
RankFROM StudentMarks
H. SELECT StudentCode as Code,NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS ValueFROM StudentMarksGROUP BY StudentCode
Answer: H

NEW QUESTION: 2
For an IP of 192 168 10.10 with a subnet mask of 255 255.240 0 an administrator is asked to provide
* The first network address
* The broadcast address, and
* The number of hosts available per subnet host
What should be the administrator's response'?
A. 192. 168.16. 0 is the network address, 192 168 31 255 is the broadcast address. There are 409J addressable hosts
B. 192. 168. 0. 1 is the network address. 192.168.10 255 is the broadcast address. There are 16382 addressable hosts
C. 192. 168. 0. 0 is the network address 192 168 15 255 is the broadcast address. There are 4094 addressable hosts
D. 192.168. 0.0 is the network address. 192 168 16 255 is the broadcast address. There are 1022 addressable hosts
Answer: C

NEW QUESTION: 3
Your network contains an Active Directory domain named contoso.com. The network contains a file server named Server1 that runs Windows Server 2012 R2. You create a folder named Folder1. You share Folder1 as Share1.
The NTFS permissions on Folder1 are shown in the Folder1 exhibit. (Click the Exhibit button.)

The Everyone group has the Full control Share permission to Folder1.
You configure a central access policy as shown in the Central Access Policy exhibit. (Click the Exhibit button.)

Members of the IT group report that they cannot modify the files in Folder1. You need to ensure that the IT group members can modify the files in Folder1. The solution must use central access policies to control the permissions. Which two actions should you perform? (Each correct answer presents part of the solution.
Choose two.)
A. On Share1, assign the Change Share permission to the IT group.
B. On the Security tab of Folder1, assign the Modify permission to the Authenticated Users group.
C. On the Security tab of Folder1, add a conditional expression to the existing permission entry for the IT group.
D. On the Security tab of Folder1, remove the permission entry for the IT group.
E. On the Classification tab of Folder1, set the classification to "Information Technology".
Answer: B,E
Explanation:
Explanation/Reference:
Explanation:
A: On the Security tab of Folder1, remove the permission entry for the IT group. => tested => it failed of course, users don't even have read permissions anymore D: On Share1, assign the Change share permission to the IT group =>Everyone already has the full control share permission => won't solve the problem which is about the NTFS Read permission E: On the Security tab of Folder1, add a conditional expression to the existing permission entry for the IT group
=> how could a condition, added to a read permission, possibly transform a read to a modify permission? If they had said "modify the permission and add a conditional expression" => ok (even if that's stupid, it works) a condition is Applied to the existing permissions to filter existing access to only matching users or groups so if we Apply a condition to a read permission, the result will only be that less users (only them matching the conditions) will get those read permissions, which actually don't solve the problem neither so only one left:
C: On the Security tab of Folder1, assign the Modify permission to the Authenticated Users group => for sure it works and it's actually the only one which works, but what about security? well i first did not consider this method => "modify" permission for every single authenticated users? But now it looks very clear:
THE MORE RESTRICTIVE PERMISSION IS ALWAYS THE ONE APPLIED!! So "Modify" for Authenticated Users group and this will be filtered by the DAC who only allows IT group. and it matches the current settings that no other user (except admin, creator owner, etc...) can even read the folder. and this link confirms my theory:
http://autodiscover.wordpress.com/2012/09/12/configuring-dynamic-access-controls- andfileclassificationpart4-winservr-2012-dac-microsoft-mvpbuzz/ Configuring Dynamic Access Controls and File Classification
Note:
In order to allow DAC permissions to go into play, allow everyone NTFS full control permissions and then DAC will overwrite it, if the user doesn't have NTFS permissions he will be denied access even if DAC grants him access.
And if this can help, a little summary of configuring DAC:

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