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NEW QUESTION: 1
What accurately describes an information map?
A. A relational data model
B. A business vocabulary
C. A conceptual data model
D. A semantic web
Answer: B

NEW QUESTION: 2
Which filing system would provide the most convenient method for the record retrieval of 200 patients consecutively admitted to the hospital?
A. unit.
B. terminal digit
C. serial unit.
D. straight numeric
Answer: D

NEW QUESTION: 3
시뮬레이션
각 목표를 확장하려면 클릭하십시오. Azure Portal에 연결하려면 브라우저 주소 표시 줄에 https://portal.azure.com을 입력하십시오.






모든 작업을 완료하면 '다음'버튼을 클릭하십시오.
'다음'버튼을 클릭하면 실험실로 돌아갈 수 없습니다. 시험의 나머지 부분을 완료하는 동안 백그라운드에서 채점됩니다.
개요
시험의 다음 섹션은 실습입니다. 이 섹션에서는 실제 환경에서 일련의 작업을 수행합니다. 실제 환경에서와 같이 대부분의 기능을 사용할수 있지만 일부 기능 (예 : 복사 및 붙여 넣기, 외부 웹 사이트 탐색 기능)은 의도적으로 설계할수 없습니다. 채점은 실험실에 명시된 작업을 수행한 결과를 기반으로 합니다. 즉, 작업 수행 방법은 중요하지 않습니다. 작업을 성공적으로 수행하면 해당 작업에 대한 크레딧을 얻게 됩니다.
실습 시간은 별도로 정해져 있지 않으며 이 시험에는 두 개 이상의 실습 과정이 있어야 합니다. 각 실습을 마치는데 시간을 많이 사용할수 있습니다. 그러나 제공된 시간 내에 실험실 및 시험의 다른 모든 섹션을 완료할수 있도록 시간을 적절히 관리해야 합니다.
랩 내에서 다음 버튼을 클릭하여 작업을 제출하면 랩으로 돌아올수 없습니다.
실습을 시작하려면 다음 버튼을 클릭하여 실습을 시작할수 있습니다.
다음 세 가지 가상 네트워크 각각에 100 개의 Azure 가상 컴퓨터를 만들 계획입니다.
* VNET1005a
* VNET1005b
* VNET1005c
3 개의 가상 네트워크 사이의 모든 네트워크 트래픽은 VNET1005a를 통해 라우팅됩니다.
가상 네트워크를 만든 다음 모든 Azure 가상 컴퓨터가 개인 IP 주소를 사용하여 다른 가상 컴퓨터에 연결할수 있도록 해야 합니다. 솔루션에는 가상 네트워크 게이트웨이가 필요하지 않으며 비용을 최소화해야 합니다.
IP 라우팅을 구성하기 전에 Azure Portal에서 무엇을 해야 합니까?
A. 1 단계 : 포털에서 자원 작성을 클릭하십시오.
2 단계 : 표시되는 새 창의 맨 위에 있는 마켓 플레이스 검색 상자에 가상 네트워크를 입력하십시오. 검색 결과에 가상 네트워크가 나타나면 클릭하십시오.
3 단계 : 나타나는 가상 네트워크 창의 배포 모델 선택 상자에서 클래식을 선택한 다음 만들기를 클릭합니다.
4 단계 : 가상 네트워크 생성 (클래식) 창에서 다음 값을 입력한 다음 생성을 클릭합니다.
이름 : VNET1005a
주소 공간 : 10.0.0.0/16
서브넷 이름 : subnet0
자원 그룹 : 새로 작성
서브넷 주소 범위 : 10.0.0.0/24
가입 및 위치 : 가입 및 위치를 선택하십시오.
5 단계 : VNET1005b (10.1.0.0/16, 10.1.0.0/24) 및 VNET1005c 10.2.0.0/16, 10.2.0.0/24)에 대해 3-5 단계를 반복하십시오.
B. 1 단계 : 포털에서 자원 작성을 클릭하십시오.
2 단계 : 표시되는 새 창의 맨 위에 있는 마켓 플레이스 검색 상자에 가상 네트워크를 입력하십시오. 검색 결과에 가상 네트워크가 나타나면 클릭하십시오.
3 단계 : 나타나는 가상 네트워크 창의 배포 모델 선택 상자에서 클래식을 선택한 다음 만들기를 클릭합니다.
4 단계 : 가상 네트워크 생성 (클래식) 창에서 다음 값을 입력한 다음 생성을 클릭합니다.
이름 : VNET1005a
주소 공간 : 10.0.0.0/18
서브넷 이름 : subnet0
자원 그룹 : 새로 작성
서브넷 주소 범위 : 10.0.0.0/26
가입 및 위치 : 가입 및 위치를 선택하십시오.
5 단계 : VNET1005b (10.1.0.0/16, 10.1.0.0/28) 및 VNET1006c 10.2.0.0/18, 10.2.0.0/24)에 대해 3-5 단계를 반복하십시오.
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/azure/virtual-network/create-virtual-network-classic

NEW QUESTION: 4
Which one of the following is a key agreement protocol used to enable two entities to agree and generate a session key (secret key used for one session) over an insecure medium without any prior secrets or communications between the entities? The negotiated key will subsequently be used for message encryption using Symmetric Cryptography.
A. PKI
B. RSA
C. Diffie_Hellmann
D. 3DES
Answer: C
Explanation:
The Diffie-Hellman key agreement protocol (also called exponential key agreement) was developed by Diffie and Hellman [DH76] in 1976 and published in the ground-breaking paper "New Directions in Cryptography." The protocol allows two users to exchange a secret key over an insecure medium without any prior secrets.
The protocol has two system parameters p and g. They are both public and may be used by all the users in a system. Parameter p is a prime number and parameter g (usually called a generator) is an integer less than p, with the following property: for every number n between 1 and p-1 inclusive, there is a power k of g such that n = gk mod p.
Suppose Alice and Bob want to agree on a shared secret key using the Diffie-Hellman key agreement protocol. They proceed as follows: First, Alice generates a random private value a and Bob generates a random private value b. Both a and b are drawn from the set of integers . Then they derive their public values using parameters p and g and their private values. Alice's public value is ga mod p and Bob's public value is gb mod p. They then exchange their public values. Finally, Alice computes gab = (gb)a mod p, and Bob computes gba = (ga)b mod p. Since gab = gba = k, Alice and Bob now have a shared secret key k.
The protocol depends on the discrete logarithm problem for its security. It assumes that it is
computationally infeasible to calculate the shared secret key k = gab mod p given the two public
values ga mod p and gb mod p when the prime p is sufficiently large. Maurer [Mau94] has shown
that breaking the Diffie-Hellman protocol is equivalent to computing discrete logarithms under
certain assumptions.
The Diffie-Hellman key exchange is vulnerable to a man-in-the-middle attack. In this attack, an
opponent Carol intercepts Alice's public value and sends her own public value to Bob. When Bob
transmits his public value, Carol substitutes it with her own and sends it to Alice. Carol and Alice
thus agree on one shared key and Carol and Bob agree on another shared key. After this
exchange, Carol simply decrypts any messages sent out by Alice or Bob, and then reads and
possibly modifies them before re-encrypting with the appropriate key and transmitting them to the
other party. This vulnerability is present because Diffie-Hellman key exchange does not
authenticate the participants. Possible solutions include the use of digital signatures and other
protocol variants.
The authenticated Diffie-Hellman key agreement protocol, or Station-to-Station (STS) protocol,
was developed by Diffie, van Oorschot, and Wiener in 1992 [DVW92] to defeat the man-in-the-
middle attack on the Diffie-Hellman key agreement protocol. The immunity is achieved by allowing
the two parties to authenticate themselves to each other by the use of digital signatures (see
Question 2
.2.2) and public-key certificates (see Question 4.1.3.10).
Roughly speaking, the basic idea is as follows. Prior to execution of the protocol, the two parties
Alice and Bob each obtain a public/private key pair and a certificate for the public key. During the
protocol, Alice computes a signature on certain messages, covering the public value ga mod p.
Bob proceeds in a similar way. Even though Carol is still able to intercept messages between Alice
and Bob, she cannot forge signatures without Alice's private key and Bob's private key. Hence, the
enhanced protocol defeats the man-in-the-middle attack.
In recent years, the original Diffie-Hellman protocol has been understood to be an example of a
much more general cryptographic technique, the common element being the derivation of a
shared secret value (that is, key) from one party's public key and another party's private key. The
parties' key pairs may be generated anew at each run of the protocol, as in the original Diffie-
Hellman protocol. The public keys may be certified, so that the parties can be authenticated and
there may be a combination of these attributes. The draft ANSI X9.42 (see
Question 5
.3.1)
illustrates some of these combinations, and a recent paper by Blake-Wilson, Johnson, and
Menezes provides some relevant security proofs.
References:
TIPTON, et. al., Official (ISC)2 Guide to the CISSP CBK 2007 edition, page 257.
And
RSA laboratoires web site: http://www.rsa.com/rsalabs/node.asp?id=2248 :

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