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NEW QUESTION: 1
When we encrypt or decrypt data there is a basic operation involving ones and zeros where they are compared in a process that looks something like this:
0101 0001 Plain text
0111 0011 Key stream
0010 0010 Output
What is this cryptographic operation called?
A. Bit Swapping
B. Decryption
C. Logical-NOR
D. Exclusive-OR
Answer: D
Explanation:
When we encrypt data we are basically taking the plaintext information and applying some key material or keystream and conducting something called an XOR or Exclusive-OR operation. The symbol used for XOR is the following: This is a type of cipher known as a stream cipher.
The operation looks like this: 0101 0001 Plain text 0111 0011 Key stream 0010 0010 Output (ciphertext)
As you can see, it's not simple addition and the XOR Operation uses something called a truth table that explains why 0+1=1 and 1+1=0.
The rules are simples, if both bits are the same the result is zero, if both bits are not the same the result is one.
The following answers are incorrect:
-Bit Swapping: Incorrect. This isn't a known cryptographic operations.
-Logical NOR: Sorry, this isn't correct but is where only 0+0=1. All other combinations of 1+1, 1+0 equals 0. More on NOR here.
-Decryption: Sorry, this is the opposite of the process of encryption or, the process of applying the keystream to the plaintext to get the resulting encrypted text.
The following reference(s) was used to create this question: For more details on XOR and all other topics of cryptography. Subscribe to our holistic http://en.wikipedia.org/wiki/Exclusive-or and http://en.wikipedia.org/wiki/Stream_cipher

NEW QUESTION: 2
Refer to the exhibit. Which three statements correctly describe Network Device A? (Choose three.)

A. With a network wide mask of 255.255.254.0, each interface does not require an IP address.
B. With a network wide mask of 255.255.255.0, must be a Layer 3 device for the PCs to communicate with each other.
C. With a network wide mask of 255.255.255.128, each interface does require an IP address on a unique IP subnet.
D. With a network wide mask of 255.255.255.128, each interface does not require an IP address.
E. With a network wide mask of 255.255.255.0, must be a Layer 2 device for the PCs to communicate with each other.
Answer: A,B,C
Explanation:
Explanation/Reference:
Explanation:
If Subnet Mask is 255.255.255.128 the hosts vary from x.x.x.0 - x.x.x.127 & x.x.x.128- x.x.x.255,so the IP Addresses of 2 hosts fall in different subnets so each interface needs an IP an address so that they can communicate each other.
If Subnet Mask is 255.255.255.0 the 2 specified hosts fall in different subnets so they need a Layer 3 device to communicate.
If Subnet Mask is 255.255.254.0 the 2 specified hosts are in same subnet so are in network address and can be accommodated in same Layer 2 domain and can communicate with each other directly using the Layer 2 address.

NEW QUESTION: 3
You are redesigning a SQL Server Analysis Services (SSAS) database that contains a
cube named Sales. Before the initial deployment of the cube, partition design was optimized for processing time. The cube currently includes five partitions named FactSalesl through FactSales5. Each partition contains from 1 million to 2 million rows.
The FactSales5 partition contains the current year's information. The other partitions contain information from prior years; one year per partition. Currently, no aggregations are defined on the partitions.
You remove fact rows that are more than five years old from the fact table in the data source and configure query logs on the SSAS server.
Several queries and reports are running very slowly.
You need to optimize the partition structure and design aggregations to improve query performance and minimize administrative overhead.
What should you do? (More than one answer choice may achieve the goal. Select the BEST answer.)
A. Use the Usage-Based Optimization Wizard to create aggregations for the current partitions.
B. Combine all the partitions into a single partition. Use the Usage-Based Optimization Wizard to create aggregations.
C. Combine all the partitions into a single partition. Use the Aggregation Design Wizard to create aggregations.
D. Use the Aggregation Design Wizard to create aggregations for the current partitions.
Answer: A

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