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NEW QUESTION: 1
Which one of the following statements is TRUE about kinesthetic learners?
A. They benefit from having information diagrammed.
B. They react well to scenarios and stories.
C. They benefit most from reading the information.
D. They prefer lectures versus hands-on experience.
E. They are hands-on learners.
Answer: B

NEW QUESTION: 2
Cardiac arrest in children is most often caused by:
A. Hypovolemia.
B. Irregular rhythm.
C. Chest trauma.
D. Respiratory compromise.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The most common complication causing pediatric cardiac arrest is inadequate breathing or other respiratory compromise.

NEW QUESTION: 3
A request arrived on your MPLS-vpn-bgp group. Due to a security breach, your customer is experiencing DoS attacks coming from specific subnets (200.0.10.0/24, 200.0.12.0/24). You have checked all MPLS-EBGP routes being advertised to BHK from other VPN sites and found four subnets listed: 200.0.10.0/24, 200.0.11.0/24, 200.0.12.0/24, 200.0.13.0/24. You immediately apply an outbound ACL filter using the appropriate MPLS-EBGP tool: access-list 1 deny 200.0.10.0 255.255.254.0 access-list 1 permit any What happens when you apply this ACL on the MPLS-EBGP connection to BHK?
A. It blocks all routes.
B. Nothing happens, no routes are blocked.
C. It blocks the routes 200.0.12.0/24, 200.0.13.0/24 only.
D. It blocks the routes 200.0.10.0/24, 200.0.13.0/24 only.
E. It blocks the routes 200.0.12.0/24, 200.0.10.0/24 only.
Answer: E
Explanation:
Remember, for the wild card mask, 1s are I DON'T CARE, and 0s are I CARE.
In the access-list we put an 0.0.0.0 255.255.254.255 network; of course 255 means "1111
1111. This means we don't care about any of the bits in the first, second & 4th octets.
In fact, the number 0 (in 0.0.0.0) is just smallest numbers we can throw there and it is easy
to type but we can use any number, it wouldn't matter, since I DON'T CARE about them
except the third octet as the wild card mask is not all "255.
Now let's extract the 0 in the third octet in binary form (so easy, right?)
0 = 0000 0000 With the 254 in the wildcard mask, we only care about the last bit of the third octet because 254 is "1111 1110. That means, if the third octet is in the form of xxxx xxx0 then it will match my access-list (x can be 0 or 1 because I DON'T CARE).
Now let's write the third octet of 4 above subnets in binary form: 10 = 0000.1010 11 = 0000.1011 12 = 0000.1100 13 = 0000.1101 So, only 10 & 12 satisfy my access list -> I will only block the routes to 200.0.12.0/24, 200.0.10.0/24 -> B is correct.
Here is a simple configuration example explaining the question above. Connect to Routers R1 and BHK via FastEthernet 0/0
Router R1 interface Loopback0 ip address 200.0.10.1 255.255.255.0 ! interface Loopback1 ip address 200.0.11.1 255.255.255.0 ! interface Loopback2 ip address 200.0.12.1 255.255.255.0 ! interface Loopback3 ip address 200.0.13.1 255.255.255.0 ! interface FastEthernet0/0 ip address 10.0.1.2 255.255.255.252 router bgp 65500 no synchronization bgp log-neighbor-changes network 10.0.1.0 mask 255.255.255.252 network 200.0.10.0 network 200.0.11.0 network 200.0.12.0 network 200.0.13.0
neighbor 10.0.1.1 remote-as 65525 no auto-summary Router BHK router bgp 65525 no synchronization bgp log-neighbor-changes network 10.0.1.0 mask 255.255.255.252 neighbor 10.0.1.2 remote-as 65500 neighbor 10.0.1.2 route-map 1 in distribute-list list in no auto-summary access-list 1 deny 0.0.0.0 255.255.254.255 access-list 1 permit any
Note: You may need to clear the BGP process on Router BHK after applying the route-map

NEW QUESTION: 4
Trading securities are securities that a bank intends to sell within a short period, usually less than:
A. Two months
B. One month
C. Quarter
D. Twenty days
Answer: B

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