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NEW QUESTION: 1

A. Option B
B. Option D
C. Option A
D. Option C
Answer: C
Explanation:
Ref: http://technet.microsoft.com/en-us/library/dn265980.aspx http://technet.microsoft.com/en-us/library/dn281956.aspx Note: Disk sharing can only be set on VHDX disks. Shared virtual hard disk functionality in guest failover clusters exclusively uses the .vhdx file format. Although the shared virtual hard disk must use the .vhdx file format for the data drive, the operating system disk for a virtual machine can use either the .vhd or the .vhdx file format.

NEW QUESTION: 2
Which are the two prerequisites for enabling star transformation on queries?
A. A bitmap index should be built on each of the foreign key columns of the fact table(s).
B. A bitmap index must exist on all the columns that are used in the filter predicates of the query.
C. A B-tree index should be built on each of the foreign key columns of the fact table(s),
D. The STAR_TRANSFORMATION_ENABLED parameter should be set to TRUE or TEMP_DISABLE.
E. A bitmap index should be built on each of the primary key columns of the fact table(s).
Answer: B,D
Explanation:
A:Enabling the transformation
E:Star transformation is essentially about adding subquery predicates corresponding to the constraint dimensions. These subquery predicates are referred to as bitmap semi-join predicates. The transformation is performed when there are indexes on the fact join columns (s.timeid, s.custid...). By driving bitmap AND and OR operations (bitmaps can be from bitmap indexes or generated from regular B-Tree indexes) of the key values supplied by the subqueries, only the relevant rows from the fact table need to be retrieved. If the filters on the dimension tables filter out a lot of data, this can be much more efficient than a full table scan on the fact table. After the relevant rows have been retrieved from the fact table, they may need to be joined back to the dimension tables, using the original predicates. In some cases, the join back can be eliminated.
Star transformation is controlled by the star_transformation_enabled parameter. The parameter takes 3 values.
TRUE - The Oracle optimizer performs transformation by identifying fact and constraint dimension tables automatically. This is done in a cost-based manner, i.e. the transformation is performed only if the cost of the transformed plan is lower than the non-transformed plan. Also the optimizer will attempt temporary table transformation automatically whenever materialization improves performance.
FALSE - The transformation is not tried.
TEMP_DISABLE - This value has similar behavior as TRUE except that temporary table transformation is not tried.
The default value of the parameter is FALSE. You have to change the parameter value and create indexes on the joining columns of the fact table to take advantage of this transformation.
Reference:Optimizer Transformations: Star Transformation

NEW QUESTION: 3
トポロジ図に示されているように、部分的な構成を持ち、RouterCに接続されたマルチレイヤーSwitchCの構成を担当しました。
ホストH1およびH2がサーバーS1に正常にpingできるように、SwitchCを構成する必要があります。また、SwitchCはサーバーS1をpingできる必要があります。
管理上の制限と要件のため、VLANを追加/削除したり、トランクリンクを作成したりしないでください。
会社のポリシーでは、静的ルーティングまたはデフォルトルーティングの使用が禁止されています。すべてのルートは、EIGRP 65010ルーティングプロトコルを介して学習する必要があります。
RouteCにアクセスできません。 RouterCが正しく構成されています。 RouterCでトランキングが設定されていません。
可能な場合、ルーテッドインターフェイスはサブネット上の最も低いホストを使用する必要があります。このソリューションを実装するには、次のサブネットを使用できます。
-10.10.10.0/24
-190.200.250.32/27
-190.200.250.64/27
ホストH1とH2は、正しいIPアドレスとデフォルトゲートウェイで構成されています。
SwitchCは、Ciscoをイネーブルパスワードとして使用します。
ルーティングは、図に示されている特定のサブネットに対してのみ有効にする必要があります。
注：管理上の制限と要件のため、VLANを追加または削除したり、VLANポートの割り当てを変更したり、トランクを作成したりしないでください。会社のポリシーでは、静的ルーティングまたはデフォルトルーティングの使用が禁止されています。すべてのルートは、EIGRPルーティングプロトコルを介して学習する必要があります。




Answer:
Explanation:
See the explanation for step by step solution:
Explanation
There are two ways to configure interVLAN routing in this case:
+ Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch. Trunking must be established between RouterC and SwitchC.+ Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer 3 switch (which supports ip routing function as a router). No trunking requires.
The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3 switch with SVIs for interVLAN routing.
We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways.
C:\>ipconfig
We will get the default gateways as follows:
Host1:+ Default gateway: 190.200.250.33
Host2:+ Default gateway: 190.200.250.65
Now we have enough information to configure SwitchC (notice the EIGRP AS in this case is 650) Note: VLAN2 and VLAN3 were created and gi0/10, gi0/11 interfaces were configured as access ports so we don't need to configure them in this sim.
SwitchC# configure terminalSwitchC(config)# no switchport -> without using this command, the simulator does not let you assign IP address on Gi0/1 interface.SwitchC(config-if)# ip address 10.10.10.2 255.255.255.0 ->RouterC has used IP 10.10.10.1 so this is the lowest usable IP address.SwitchC(config-if)# no shutdown SwitchC(config)# int vlan 2 SwitchC(config-if)# ip address 190.200.250.33 255.255.255.224SwitchC(config-if)# no shutdown SwitchC(config-if)# int vlan 3SwitchC(config-if)# ip address 190.200.250.65 255.255.255.224 SwitchC(config-if)# no shutdownSwitchC(config-if)#exitSwitchC(config)# ip routing (Notice: MLS will not work without this command)SwitchC(config)# router eigrp 650SwitchC(config-router)# network 10.10.10.0
0.0.0.255SwitchC(config-router)# network 190.200.250.32 0.0.0.31SwitchC(config-router)# network
190.200.250.64 0.0.0.31
NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the exam , also don't modify/delete any port just do the above configuration. Also some reports said the "no auto-summary" command can't be used in the simulator, in fact it is not necessary because the network 190.200.0.0/16 is not used anywhere else in this topology.
In order to complete the lab, you should expect the ping to SERVER to succeed from the MLS , and from the PCs as well.
Also make sure you use the correct EIGRP AS number (in the configuration above it is 650 but it will change when you take the exam) but we are not allowed to access RouterC so the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS number, no neighbor relationship is formed between RouterC and SwitchC.
In fact, we are pretty sure instead of using two commands "network 190.200.250.32 0.0.0.31 and "network
190.200.250.64 0.0.0.31 we can use one simple command "network 190.200.0.0 because it is the nature of distance vector routing protocol like EIGRP: only major networks need to be advertised; even without "no auto-summary" command the network still works correctly. But in the exam the sim is just a flash based simulator so we should use two above commands, just for sure. But after finishing the configuration, we can use "show run" command to verify, only the summarized network 190.200.0.0 is shown.

NEW QUESTION: 4
You have a server named SQL1 that has SQL Server 2014 installed. SQL1 has 32 processor cores and 64 GB of RAM.
SQL1 hosts a database used for a public-facing marketing website. SQL1 performs Online Transaction Processing (OLTP) operations only.
Several of the queries that run on SQL1 use the 32 processor cores and complete in 30 ms.
You need to reduce the number of queries that use multiple cores. The solution must also reduce the number of processor cores used by the queries that require multiple processor cores.
Which two database settings should you modify? To answer, select the appropriate settings in the answer area.

Answer:
Explanation:
Explanation

Cost Threshold for Parallelism
The cost threshold for parallelism option specifies the threshold at which SQL Server creates and runs parallel plans for queries. SQL Server creates and runs a parallel plan for a query only when the estimated cost to run a serial plan for the same query is higher than the value set in cost threshold for parallelism. The cost refers to an estimated cost required to run the serial plan on a specific hardware configuration, and is not a unit of time.
The cost threshold for parallelism option can be set to any value from 0 through 32767. The default value is 5.
Max Degree of Parallelism
When an instance of SQL Server runs on a computer that has more than one microprocessor or CPU, it detects the best degree of parallelism, that is, the number of processors employed to run a single statement, for each parallel plan execution. You can use the max degree of parallelism option to limit the number of processors to use in parallel plan execution.
References:
https://docs.microsoft.com/en-us/sql/database-engine/configure-windows/configure-the-cost-threshold-for-parall

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