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NEW QUESTION: 1
In the project time management knowledge area, there are six processes. According to the PMBOK, which project time knowledge area will have the majority of the effort?
A. Control schedule
B. Define activities
C. Estimate activity resources
D. Develop schedule
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Of all six processes, the control schedule process will take the majority of the time in the project time management knowledge area. Control schedule process is a method of monitoring the status of the project to update project progress and deal with the changes to the schedule baseline. It is concerned with:
Determining the current status of the project

Influencing the factors that create schedule changes

Determining that the project schedule has changed

Managing the actual changes as they occur

Control schedule is a component of the

Perform Integration Change Control process.

Incorrect Answers:
A, B, D: These processes will not take the longest to complete.

NEW QUESTION: 2
A customer with Avaya Aura Contact Center (AACC) wants callers, who are waiting to be answered by an agent, to hear a series of three different recorded announcements while they are waiting in the queue.
If the customer is still on hold after hearing all three messages, the series of three messages should continue to be repeated until the caller is presented to an agent.
Which section of script would accomplish this scenario?
A. SECTION wait_loop
ASSIGN 1 TO loop_counter_cv
WHERE loop_counter_cv EQUALS
VALUE 1: GIVE RAN 15
VALUE 2: GIVE RAN 16
VALUE 3: GIVE RAN 17
DEFAULT: ASSIGN loop_counter_cv + 1 TO loop_counter_cv
END WHERE
WAIT 30
EXECUTE wait_loop
B. ASSIGN 1 TO loop_counter_cv
SECTION wait_loop
WHERE loop_counter_cv EQUALS
VALUE 1: GIVE RAN 15
VALUE 2: GIVE RAN 16
VALUE 3: GIVE RAN 17
DEFAULT: ASSIGN 0 TO loop_counter_cv
END WHERE
ASSIGN loop_counter_cv + 1 TO loop_counter_cv
WAIT 30
EXECUTE wait_loop
C. ASSIGN 1 TO loop_counter_cv
SECTION wait_loop
WHERE loop_counter_cv EQUALS
VALUE 1: GIVE RAN 15
VALUE 2: GIVE RAN 16
VALUE 3: GIVE RAN 17
DEFAULT:
END WHERE
ASSIGN loop_counter_cv + 1 TO loop_counter_cv
WAIT 30
EXECUTE wait_loop
D. ASSIGN 1 TO loop_counter_cv
SECTION wait_loop
WHERE loop_counter_cv EQUALS
VALUE 1: GIVE RAN 15
VALUE 2: GIVE RAN 16
VALUE 3: GIVE RAN 17
DEFAULT: ASSIGN loop_counter_cv + 1 TO loop_counter_cv
END WHERE
WAIT 30
EXECUTE wait_loop
Answer: A

NEW QUESTION: 3
Which feature of IBM Cognos Disclosure Management ensures that all reports deliver a single, consistent version of the truth?
A. Link report data directly to enterprise data sources
B. Controlled collaboration
C. Microsoft Office interface
D. Workflow and task management capabilities.
Answer: A

NEW QUESTION: 4
Evaluate the following CREATE TABLE commands:
CREATE TABLE orders
(ord_no NUMBER(2) CONSTRAINT ord_pk PRIMARY KEY,
ord_date DATE,
cust_id NUMBER(4));
CREATE TABLE ord_items
(ord_no NUMBER(2),
item_no NUMBER(3),
qty NUMBER(3) CHECK (qty BETWEEN 100 AND 200),
expiry_date date CHECK (expiry_date > SYSDATE),
CONSTRAINT it_pk PRIMARY KEY (ord_no,item_no),
CONSTRAINT ord_fk FOREIGN KEY(ord_no) REFERENCES orders(ord_no));
Why would the ORD_ITEMS table not get created?
A. The BETWEEN clause cannot be used for the CHECK constraint.
B. SYSDATE cannot be used with the CHECK constraint.
C. The CHECK constraint cannot be used twice for the same table.
D. ORD_NO and ITEM_NO cannot be used as a composite primary key because ORD_NO is also the FOREIGN KEY.
Answer: B

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