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NEW QUESTION: 1
You are troubleshooting an eMac that has no image on its built-in display. You have already checked user controls and reset PRAM, but the issue persists. When you connect an external display to the eMac's VGA output port and restart the eMac, you see a proper image on the external display. Which of the following service modules would most likely be the cause of these symptoms?
A. Hard drive
B. Logic Board
C. Display Analog Assembly
D. Power Supply Assembly
Answer: C

NEW QUESTION: 2
The type of discretionary access control (DAC) that is based on an individual's identity is also called:
A. Identity-based Access control
B. Non-Discretionary Access Control
C. Lattice-based Access control
D. Rule-based Access control
Answer: A
Explanation:
An identity-based access control is a type of Discretionary Access Control
(DAC) that is based on an individual's identity.
DAC is good for low level security environment. The owner of the file decides who has
access to the file.
If a user creates a file, he is the owner of that file. An identifier for this user is placed in the
file header and/or in an access control matrix within the operating system.
Ownership might also be granted to a specific individual. For example, a manager for a
certain department might be made the owner of the files and resources within her
department. A system that uses discretionary access control (DAC) enables the owner of
the resource to specify which subjects can access specific resources.
This model is called discretionary because the control of access is based on the discretion
of the owner. Many times department managers, or business unit managers , are the
owners of the data within their specific department. Being the owner, they can specify who
should have access and who should not.
Reference(s) used for this question:
Harris, Shon (2012-10-18). CISSP All-in-One Exam Guide, 6th Edition (p. 220). McGraw-
Hill . Kindle Edition.

NEW QUESTION: 3
What is the output of the program given below?
#include <iostream>
using namespace std;
int main (int argc, const char * argv[])
{
float f=?10.501;
cout<<(int)f;
}
A. 0
B. ?11
C. ?10
D. 1
Answer: C

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