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NEW QUESTION: 1
-- Exhibit -user@router# run show log ospf-test ... Jun 10 22:35:38.598494 OSPF sent Hello 10.100.0.1 -> 224.0.0.5 (ge-1/0/3.1000 IFL 77
area 0.0.0.0) Jun 10 22:35:38.598520 Version 2, length 44, ID 10.100.1.2, area 0.0.0.0 Jun 10 22:35:38.598543 mask 255.255.255.252, hello_ivl 10, opts 0x2, prio 128 Jun 10 22:35:38.598564 dead_ivl 32, DR 10.100.0.1, BDR 0.0.0.0 Jun 10 22:35:41.522956 OSPF periodic xmit from 10.200.26.1 to 224.0.0.5 (IFL
2684276196 area 0.0.0.1)
Jun 10 22:35:42.798220 OSPF rcvd Hello 10.100.0.2 -> 224.0.0.5 (ge-1/0/3.1000 IFL 77
area 0.0.0.0)
Jun 10 22:35:42.798311 Version 2, length 48, ID 10.100.1.1, area 0.0.0.0
Jun 10 22:35:42.798334 checksum 0x0, authtype 0
Jun 10 22:35:42.798356 mask 255.255.255.252, hello_ivl 10, opts 0x2, prio 128
Jun 10 22:35:42.798377 dead_ivl 40, DR 10.100.0.2, BDR 10.100.0.1
Jun 10 22:35:45.189034 OSPF rcvd Hello 10.100.0.2 -> 224.0.0.5 (ge-1/0/3.1000 IFL 77 area 0.0.0.0) Jun 10 22:35:45.189097 Version 2, length 44, ID 10.100.1.1, area 0.0.0.0 Jun 10 22:35:45.189118 checksum 0x0, authtype 0 Jun 10 22:35:45.189140 mask 255.255.255.252, hello_ivl 10, opts 0x2, prio 128 Jun 10 22:35:45.189162 dead_ivl 40, DR 10.100.0.2, BDR 0.0.0.0
Jun 10 22:35:45.196969 OSPF DR is 10.100.1.2, BDR is 0.0.0.0 Jun 10 22:35:45.197050 OSPF sent Hello 10.200.26.1 -> 224.0.0.5 (ge-1/0/0.0 IFL 69 area 0.0.0.1)
Jun 10 22:35:45.197076 Version 2, length 44, ID 10.100.1.2, area 0.0.0.1 Jun 10 22:35:45.197098 mask 255.255.255.252, hello_ivl 10, opts 0x2, prio 128 Jun 10 22:35:45.197119 dead_ivl 40, DR 10.200.26.1, BDR 0.0.0.0 Jun 10 22:35:46.746900 OSPF periodic xmit from 10.100.0.1 to 224.0.0.5 (IFL 2684276196
area 0.0.0.0) -- Exhibit -
Click the Exhibit button.
Referring to the exhibit, what is preventing the OSPF neighborship with two directly connected routers using interface ge-1/0/3 from reaching the full state?
A. authentication type mismatch
B. subnet mismatch
C. dead interval mismatch
D. hello interval mismatch
Answer: C

NEW QUESTION: 2
When you are editing an intrusion policy, how do you know that you have changes?
A. You are prompted to save your changes on every screen refresh.
B. A yellow, triangular icon displays next to the Policy Information option in the navigation panel.
C. The Commit Changes button is enabled.
D. A system message notifies you.
Answer: B

NEW QUESTION: 3
Identify the network topology from below diagram presented below:

Network Topology
A. Mesh
B. Ring
C. Star
D. Bus
Answer: C
Explanation:
Explanation/Reference:
For your exam you should know the information below related to LAN topologies:
LAN Topologies
Network topology is the physical arrangement of the various elements (links, nodes, etc.) of a computer network.
Essentially, it is the topological structure of a network, and may be depicted physically or logically. Physical topology refers to the placement of the network's various components, including device location and cable installation, while logical topology shows how data flows within a network, regardless of its physical design.
Distances between nodes, physical interconnections, transmission rates, and/or signal types may differ between two networks, yet their topologies may be identical.
Bus
In local area networks where bus topology is used, each node is connected to a single cable. Each computer or server is connected to the single bus cable. A signal from the source travels in both directions to all machines connected on the bus cable until it finds the intended recipient. If the machine address does not match the intended address for the data, the machine ignores the data. Alternatively, if the data matches the machine address, the data is accepted. Since the bus topology consists of only one wire, it is rather inexpensive to implement when compared to other topologies. However, the low cost of implementing the technology is offset by the high cost of managing the network. Additionally, since only one cable is utilized, it can be the single point of failure. If the network cable is terminated on both ends and when without termination data transfer stop and when cable breaks, the entire network will be down.
Bus topology
Graphic from:

http://www.technologyuk.net/telecommunications/networks/images/bus_topology.gif Linear bus The type of network topology in which all of the nodes of the network are connected to a common transmission medium which has exactly two endpoints (this is the 'bus', which is also commonly referred to as the backbone, or trunk) - all data that is transmitted between nodes in the network is transmitted over this common transmission medium and is able to be received by all nodes in the network simultaneously.
Distributed bus
The type of network topology in which all of the nodes of the network are connected to a common transmission medium which has more than two endpoints that are created by adding branches to the main section of the transmission medium - the physical distributed bus topology functions in exactly the same fashion as the physical linear bus topology (i.e., all nodes share a common transmission medium).
Star
In local area networks with a star topology, each network host is connected to a central point with a point- to-point connection. In Star topology every node (computer workstation or any other peripheral) is connected to central node called hub or switch.
The switch is the server and the peripherals are the clients. The network does not necessarily have to resemble a star to be classified as a star network, but all of the nodes on the network must be connected to one central device.
All traffic that traverses the network passes through the central point. The central point acts as a signal repeater.
The star topology is considered the easiest topology to design and implement. An advantage of the star topology is the simplicity of adding additional nodes. The primary disadvantage of the star topology is that the central point represents a single point of failure.
Star Topology

Image from: http://fcit.usf.edu/network/chap5/pics/star.gif
Ring
A network topology that is set up in a circular fashion in which data travels around the ring in one direction and each device on the ring acts as a repeater to keep the signal strong as it travels. Each device incorporates a receiver for the incoming signal and a transmitter to send the data on to the next device in the ring.
The network is dependent on the ability of the signal to travel around the ring. When a device sends data, it must travel through each device on the ring until it reaches its destination. Every node is a critical link. If one node goes down the whole link would be affected.
Ring Topology

Image from: https://forrester-infosystems.wikispaces.com/
Mesh
The value of a fully meshed networks is proportional to the exponent of the number of subscribers, assuming that communicating groups of any two endpoints, up to and including all the endpoints, is approximated by Reed's Law.
A mesh network provides for high availability and redundancy. However, the cost of such network could be very expensive if dozens of devices are in the mesh.
Mesh Topology

Image from: http://www.technologyuk.net/telecommunications/networks/images/mesh_topology.gif Fully connected mesh topology A fully connected network is a communication network in which each of the nodes is connected to each other. In graph theory it known as a complete graph. A fully connected network doesn't need to use switching nor broadcasting. However, its major disadvantage is that the number of connections grows quadratic ally with the number of nodes, so it is extremely impractical for large networks. A two-node network is technically a fully connected network.
Partially connected mesh topology
The type of network topology in which some of the nodes of the network are connected to more than one other node in the network with a point-to-point link - this makes it possible to take advantage of some of the redundancy that is provided by a physical fully connected mesh topology without the expense and complexity required for a connection between every node in the network.
The following answers are incorrect:
The other options presented are not valid.
The following reference(s) were/was used to create this question:
CISA review manual 2014, Page number 262

NEW QUESTION: 4
A seller's price is below an appropriate measure of casts. Moreover, the seller has a reasonable prospect of recovering the resulting loss in the future through higher prices or a greater market share. Accordingly, the seller has engaged in:
A. Collusive pricing.
B. Dumping.
C. Price discrimination.
D. Predatory pricing.
Answer: D
Explanation:
Predatory pricing is intentionally pricing below cost to eliminate competition and reduce supply. Federal statutes and many state laws prohibit the practice. The U.S. Supreme Court has held that pricing is predatory when two conditions are met: 1) the seller's price is below an appropriate measure of its costs," and 2) it has a reasonable prospect of
recovering the resulting IOSS through higher prices or greater market share.

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