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NEW QUESTION: 1

A. CA
B. CRL
C. OID
D. CSR
Answer: B

NEW QUESTION: 2
Referring to the exhibit, whi ch LIF role is required to copy to cloud with this NetApp Data Availability Services (NDAS) solu tion?
A. data
B. cluster
C. inter cluster
D. node management
Answer: C

NEW QUESTION: 3
A consultant has been hired by the V.P. of a large financial organization to assess the company's security posture. During the security testing, the consultant comes across child pornography on the V.P.'s computer. What is the consultant's obligation to the financial organization?
A. Stop work immediately and contact the authorities.
B. Say nothing and continue with the security testing.
C. Delete the pornography, say nothing, and continue security testing.
D. Bring the discovery to the financial organization's human resource department.
Answer: A

NEW QUESTION: 4
You have a database that contains the tables shown in the exhibit. (Click the Exhibit button).

You need to create a query for a report. The query must meet the following requirements:
NOT use object delimiters.
Return the most recent orders first.
Use the first initial of the table as an alias.
Return the most recent order date for each customer.
Retrieve the last name of the person who placed the order.
Return the order date in a column named MostRecentOrderDate that appears as the last column in the report.
The solution must support the ANSI SQL-99 standard.
Which code segment should you use?
To answer, type the correct code in the answer area.
A. select C.Lastname, P.MostRecentOrderDate from customers AS C inner join ( select customID, MostRecentOrderDate=max(orderDate) from orders group by customID
)P
on C.customerID=P.CustomerID
order by P.MostRecentOrderDate desc
B. SELECT LastName, O.OrderDate AS MostRecentOrderDate FROM Customers AS C INNER JOIN Orders AS O ON CustomerID = O.CustomerID ORDER BY O.OrderDate DESC
C. SELECT c.CustomerID --optional c.LastName, max(o.OrderDate) 'MostRecentOrderDate' FROM Customer c LEFT OUTER JOIN Orders o ON o.CustomerID = c.CustomerID GROUP BY c.CustomerID, c.LastName ORDER BY 3 DESC
Answer: C
Explanation:
--Burgos -NO Command equal to Derek, but without subquery. I Think that is better put c. CustomerID to identifies duplicated LastName. I used "OUTER JOIN" to permit that customers that had "no orders" appears too. SELECT c.CustomerID --optional c.LastName, max(o.OrderDate) 'MostRecentOrderDate' FROM Customer c LEFT OUTER JOIN Orders o ON o.CustomerID = c.CustomerID GROUP BY c.CustomerID, c.LastName ORDER BY o.OrderDate DESC --\Burgos
According to the table spec, lastname is not unique key. So my answer is
select C.Lastname, P.MostRecentOrderDate from customers AS C inner join ( select customID, MostRecentOrderDate=max(orderDate) from orders group by customID )P on C.customerID=P.CustomerID order by P.MostRecentOrderDate desc
--Derek =================================== The previous one missed "Group By" and did not consider the case of duplicate last names. SELECT C.LastName, O.OrderDate AS MostRecentOrderDate FROM Customers AS C INNER JOIN Orders AS O ON C.CustomerID = O.CustomerID ORDER BY O.OrderDate DESC

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