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NEW QUESTION: 1

A. Option C
B. Option B
C. Option A
Answer: A

NEW QUESTION: 2
展示を参照してください。

R1のEthernet0 / 0にサブインターフェイスを追加して、IPアドレスを持つVLAN 20を許可するために必要なコマンド
10.20.20.1/24？
A. R1（config）#interface ethernet0 / 0.20
R1（config）#encapsulation dot1q 20
R1（config）#ipアドレス10.20.20.1 255.255.255.0
B. R1（config）#interface ethernet0 / 0
R1（config）#ipアドレス10.20.20.1 255.255.255.0
C. R1（config）#interface ethernet0 / 0.20
R1（config）#ipアドレス10.20.20.1 255.255.255.0
D. R1（config）#interface ethernet0 / 0
R1（config）#encapsulation dot1q 20
R1（config）#ipアドレス10.20.20.1 255.255.255.0
Answer: A

NEW QUESTION: 3

A. slmgr.vbs computcr2 /dlv
B. ospp.vbs /tokact:computer2
C. winrs.exe -r:Computer2 netdom.exe
D. Get-RDLicenseConfiguration computer2
Answer: A
Explanation:
Explanation
http://www.howtogeek.com/245445/how-to-use-slmgr-to-change-remove-or-extend-your-windows-license/

NEW QUESTION: 4



A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
F. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
G. CustNo
H. CustNoWHERE D.CustNo IS NULL
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
J. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
Answer: E
Explanation:
Explanation
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

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