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NEW QUESTION: 1
The implementations group has been using the test bed to do a `proof-of-concept' that requires both Client 1 and Client 2 to access the WEB Server at 209.65.200.241. After several changes to the network addressing, routing schemes, DHCP services, NTP services, layer 2 connectivity, FHRP services, and device security, a trouble ticket has been opened indicating that Client 1 cannot ping the 209.65.200.241 address.
Use the supported commands to isolate the cause of this fault and answer the following question.
On which device is the fault condition located?


A. R3
B. DSW2
C. R4
D. DSW1
E. R2
F. R1
G. ASW2
H. ASW1
Answer: C

NEW QUESTION: 2
By default, what is the maximum number of Cache Nodes you can run in Amazon ElastiCache?
A. 0
B. 1
C. 2
D. 3
Answer: A
Explanation:
Explanation/Reference:
Explanation:
In Amazon ElastiCache, you can run a maximum of 20 Cache Nodes.

NEW QUESTION: 3
Which statement is FALSE about the ESB profile?
A. By default,ESB profile considers all messages consumed from a queue as a SOAP message.
B. When the JMS transport is enabled on a proxy service, ESB profile will start listening on a JMS queue with the same name as the proxy service.
C. By setting the transport.jms.MessageType parameter with the respective content type, you can read different message formats from a queue.
D. ESB profile can work with any JMS broker that offers JNDI support.
Answer: C

NEW QUESTION: 4
View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables.
You need to create a view that displays the ORDER ID, ORDER_DATE, and the total number of items in each order.

Which CREATE VIEW statement would create the view successfully?
A. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)ll' NO OF ITEMS'
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date
WITH CHECK OPTION;
B. CREATE OR REPLACE VIEW ord_vu (order_id,order_date)
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
C. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
D. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
Answer: D

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