Name: JN0-335 Customizable Exam Mode
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NEW QUESTION: 1
Prerequisite:
A sorted input dataset with record length 100 contains at least one record for each of the values '1', '2', '3'
in the first byte. The applied sort criteria is 1,100,ch,a.
Requirements:
1 .) All records with '1' in the first byte must be ignored.
2 .) All records with '2' in the first byte must be written to the output dataset.
3 .) If there is a '3' in the first byte, the read iteration must be left.
4 .) The program must not abend or loop infinitely.
If the code below does not fulfill the specifications provided above, which of the following is the most likely
reason?
DCL DDIN FILE RECORD INPUT;
DCL DDOUT FILE RECORD OUTPUT;
DCL 1 INSTRUC,
3 A CHAR(1),
3 * CHAR(99);
DCL EOF_IN BIT(1) INIT('0'B);
DCL (Z1,Z2,Z3,ZO) BIN FIXED(31) INIT(0);
ON ENDFILE(DDIN) EOF_IN = '1'B;
READ FILE(DDIN) INTO (INSTRUC);
LOOP: DO WHILE (

Related Exams

EOF_IN);
SELECT(INSTRUC.A);
WHEN('1') DO;
Z1 +-= Z1;
ITERATE LOOP;
END;
WHEN('3') DO;
Z3 = Z3+1;
LEAVE LOOP;
END;
WHEN('2') DO;
Z2 = Z2+1;
WRITE FILE(DDOUT) FROM(INSTRUC);
END;
OTHER DO;
ZO = ZO+1;
PUT SKIP LIST(INSTRUC.A);
END;
END;/*select*/
READ FILE(DDIN) INTO(INSTRUC);
END ;/*loop*/
A. The code fulfills the requirement.
B. The code does not fulfill the requirement because the program will loop infinitely.
C. The code does not fulfill the requirement because not all records with '2' in the first byte will be written to the output dataset.
D. The code does not fulfill the requirement because the last record with '2' in the first byte will be written twice to the output dataset.
Answer: B

NEW QUESTION: 2
For a given mean, which distribution would you prefer for frequency modeling where operational risk events are considered dependent, or in other words are seen as clustering together (as opposed to being independent)?
A. Gamma
B. Binomial
C. Poisson
D. Negative binomial
Answer: D
Explanation:
Explanation
An interesting property that distinguishes the three most used distributions for modeling event frequency is that for a given mean, their variances differ. The ratio of variance to mean (the variance-mean ratio, calculated as variance/mean) can then be used to decide the kind of distribution to use. Both the variance and the mean can be estimated from available data points from the internal or external loss databases, or the scenario exercise.
The variance-mean ratio reflects how dispersed a distribution is. (In the PRMIA handbook, the variance to mean ratio has been described as the "Q-Factor".) The Poisson distribution has its mean equal to its variance, and therefore the variance to mean ratio is 1. For the negative binomial distribution, this ratio is always greater than 1, which means there is greater dispersion compared to the mean - or more intervals with low counts as well as more intervals with high counts. For the binomial distribution, the variance to mean ratio is less than one, which means it is less dispersed than the Poisson distribution with values closer to the mean.
In a situation where operational risk events are seen as clustering together, or dependent, the variance will be higher and it would be more appropriate to use the negative binomial distribution.

NEW QUESTION: 3
You have a Microsoft Exchange Online subscription.
You need to prevent all Android devices from using Exchange ActiveSync to sync email. Other devices must be allowed to sync email by using Exchange ActiveSync.
What should you use?
A. mobile device mailbox policies
B. device access rules
C. Exchange ActiveSync access settings
D. data loss prevention (DLP) policies
Answer: B
Explanation:
Reference:
https://docs.microsoft.com/en-us/powershell/module/exchange/new-activesyncdeviceaccessrule?view=exchange-ps

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