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NEW QUESTION: 1
James works as a Database Designer for AccessSoft Inc. The company has a Windows Vista computer, which has a database named Orders. The database contains a table named OrderDetails. Users run queries against the database to place orders of customers. They also retrieve data related to the processing of orders and information about the customers who place orders. Users complain that the retrieval of data is very slow. James opens the following query:
SELECT * FROM OrderDetails;
What should he do to enhance the performance of the query?
A. Use the TOP clause with the SELECT statement.
B. Use the GROUP BY clause with the SELECT statement.
C. Use the WHERE clause with the SELECT statement.
D. Use the DISTINCT clause with the SELECT statement.
Answer: C
Explanation:
In order to enhance the performance of the query, James will use the WHERE clause with the SELECT statement as follows:
SELECT * FROM OrderDetails WHERE custname='customer name';
The WHERE clause is used to filter data given in the table. The filter is based on one or more columns given after the SELECT statement. The columns are separated by commas.
Answer option C is incorrect. The DISTINCT clause is used to prevent rows from getting duplicated in the result set. It can only be used with the SQL SELECT statement.
The syntax for the DISTINCT clause is as follows:
SELECT DISTINCT <columns>
FROM <table_name>
WHERE <conditions>
Answer option B is incorrect. The TOP clause is used to retrieve data for the first set of rows. The example is as follows:
SELECT * TOP 10 FROM OrderDetails;
The statement will retrieve only the top ten rows from the OrderDetails table.
Answer option D is incorrect. The GROUP BY clause groups selected rows on the basis of values of specified column(s) for each row, and returns a single row of summary information for each group. Rows that have the same values in the specified grouping column(s) are grouped together. The GROUP BY clause suppresses duplicate rows for the grouping column(s). It does not guarantee the order of the result set. Therefore, the ORDER BY clause should be used with the GROUP BY clause to sort the result set in the desired order. The syntax of the GROUP BY clause is given below:
SELECT column_name, aggregate_function(column_name) FROM table_name WHERE column_name operator value GROUP BY column_name Consider the following example, EMPLOYEE_EXPENSES table:
P_ID
LastName
Expenses
1
Harry
1000
2
Steve
400
3
Harry
2000
To group the total sum (total order) of each employee from the EMPLOYEE_EXPENSES table, run the following command:
SELECT LastName, Expenses FROM Orders GROUP BY LastName
The output of the command will appear as:
LastName
Expenses
Harry
3000
Steve
400
Chapter: DATABASE, ADVANCED-LEVEL
Objective: Query Design

NEW QUESTION: 2
A customer is hosting an application and wants to test Jitter Smoothing to determine if it will help improve application performance.
Which combination of HPE hardware and software will allow them to accomplish this task?
A. HPE iLO 4 with iLO Advanced Premium Security Edition license
B. HPE iLO 4 with iLO Advanced license
C. HPE iLO 5 with Standard license
D. HPE iLO 5 with iLO Advanced license
Answer: C

NEW QUESTION: 3



R1# show running-config
interface Loopback0
description ***Loopback***
ip address 192.168.1.1 255.255.255.255
ip ospf 1 area 0
!
interface Ethernet0/0
description **Connected to R1-LAN**
ip address 10.10.110.1 255.255.255.0
ip ospf 1 area 0
!
interface Ethernet0/1
description **Connected to L2SW**
ip address 10.10.230.1 255.255.255.0
ip ospf hello-interval 25
ip ospf 1 area 0
!
router ospf 1
log-adjacency-changes

R2# show running-config
R2
!
interface Loopback0
description **Loopback**
ip address 192.168.2.2 255.255.255.255
ip ospf 2 area 0
!
interface Ethernet0/0
description **Connected to R2-LAN**
ip address 10.10.120.1 255.255.255.0
ip ospf 2 area 0
!
interface Ethernet0/1
description **Connected to L2SW**
ip address 10.10.230.2 255.255.255.0
ip ospf 2 area 0
!
router ospf 2
log-adjacency-changes

R3# show running-config
R3
username R6 password CISCO36
!
interface Loopback0
description **Loopback**
ip address 192.168.3.3 255.255.255.255
ip ospf 3 area 0
!
interface Ethernet0/0
description **Connected to L2SW**
ip address 10.10.230.3 255.255.255.0
ip ospf 3 area 0
!
interface Serial1/0
description **Connected to R4-Branch1 office**
ip address 10.10.240.1 255.255.255.252
encapsulation ppp
ip ospf 3 area 0
!
interface Serial1/1
description **Connected to R5-Branch2 office**
ip address 10.10.240.5 255.255.255.252
encapsulation ppp
ip ospf hello-interval 50
ip ospf 3 area 0
!
interface Serial1/2
description **Connected to R6-Branch3 office**
ip address 10.10.240.9 255.255.255.252
encapsulation ppp
ip ospf 3 area 0
ppp authentication chap
!
router ospf 3
router-id 192.168.3.3
!

R4# show running-config
R4
!
interface Loopback0
description **Loopback**
ip address 192.168.4.4 255.255.255.255
ip ospf 4 area 2
!
interface Ethernet0/0
ip address 172.16.113.1 255.255.255.0
ip ospf 4 area 2
!
interface Serial1/0
description **Connected to R3-Main Branch office**
ip address 10.10.240.2 255.255.255.252
encapsulation ppp
ip ospf 4 area 2
!
router ospf 4
log-adjacency-changes

R5# show running-config
R5
!
interface Loopback0
description **Loopback**
ip address 192.168.5.5 255.255.255.255
ip ospf 5 area 0
!
interface Ethernet0/0
ip address 172.16.114.1 255.255.255.0
ip ospf 5 area 0
!
interface Serial1/0
description **Connected to R3-Main Branch office**
ip address 10.10.240.6 255.255.255.252
encapsulation ppp
ip ospf 5 area 0
!
router ospf 5
log-adjacency-changes

R6# show running-config
R6
username R3 password CISCO36
!
interface Loopback0
description **Loopback**
ip address 192.168.6.6 255.255.255.255
ip ospf 6 area 0
!
interface Ethernet0/0
ip address 172.16.115.1 255.255.255.0
ip ospf 6 area 0
!
interface Serial1/0
description **Connected to R3-Main Branch office**
ip address 10.10.240.10 255.255.255.252
encapsulation ppp
ip ospf 6 area 0
ppp authentication chap
!
router ospf 6
router-id 192.168.3.3
!


A. Option A
B. Option D
C. Option B
D. Option C
Answer: B

NEW QUESTION: 4
You are the program manager for your organization. You are examining the order of the activities in your program schedule and would like to change some of the ordering to alleviate scheduling conflicts, risks, and based on your experience with the discipline the program uses. Some of the activities you can rearrange while some of the activities must be completed in a particular order. What term describes the activities that can happen in any order?
A. Discretionary dependencies
B. Mandatory dependencies
C. Finish on constraints
D. Benefits management dependencies
Answer: A

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