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NEW QUESTION: 1
実装グループは、テストベッドを使用して「概念実証」を行っています。これは、クライアント1とクライアント2の両方が209.65.200.241のWEBサーバーにアクセスすることを必要とします。ネットワークアドレス指定、ルーティングスキーム、DHCPサービス、NTPサービス、レイヤー2接続、FHRPサービス、およびデバイスセキュリティにいくつかの変更を加えた後、クライアント1が209.65.200.241アドレスにpingできないことを示すトラブルチケットが開かれました。
サポートされているコマンドを使用して、この障害の原因を特定し、次の質問に答えてください。
障害状態はどのテクノロジーに関連していますか？
A. IPv4 OSPF Routing
B. IPv6 RIP Routing
C. IP DHCP Server
D. IPv4 Route Redistribution
E. IPv6 OSPF Routing
F. NTP
G. IPv4 and IPv6 Interoperability
H. IPv4 layer 3 security
I. IPv4 EIGRP Routing
Answer: D
Explanation:
説明
R4では、EIGRPルーティングプロトコルの再配布で、ルートマップの名前を変更して問題を解決する必要があります。ルートマップOSPF_to_EIGRPを参照しますが、実際のルートマップはOSPF-> EIGRPと呼ばれます。

NEW QUESTION: 2
Which two CGE end-user groups do NOT currently have their profile settings retained between sessions? (Choose two.)
A. Engineers
B. Technicians
C. Executives/Management
D. Sales
Answer: C,D

NEW QUESTION: 3
組織はクラウドに移行したいと考えています。安全な暗号化されたデータベースストレージオプションを探しています。
以下のAWS機能のうち、これを達成するのに役立つものはどれですか？
A. Redshiftを使用した多層暗号化
B. EBSを使用したAWS MFA
C. AWS EBS暗号化
D. AWS S3サーバー側のストレージ
Answer: C
Explanation:
説明
AWS EBSは、新しいボリュームの作成中にボリュームの暗号化をサポートします。スナップショットが暗号化されたボリュームから作成される場合、既存のスナップショットからのボリュームの作成もサポートします。保管中のデータ、I / O、およびEBSのすべてのスナップショットが暗号化されます。暗号化は、EC2インスタンスをホストするサーバーで行われ、EC2インスタンスとEBSストレージ間を移動するデータの暗号化を提供します。 EBS暗号化は、業界標準であるAES-256暗号化アルゴリズムに基づいています

NEW QUESTION: 4



A. public Class Generator implement IdGenerator (
Private int id =0;
Public int getNextId { ) {
Synchronized (id) ;
return ++id
}
}
}
Return ++id;
B. public class Generator implements IdGeneretor (
Private int id =0;
Public int getNExtId {) {
Synchronized (new generator()) {
return ++id;
}
}
}
C. public Class Generator implement IdGenerator (
privateAtcmicinInteger id - new AtomaticIntegger (0);
public int getNextId{} {
return id. Increaseincrasement AndSet{) ;
}
}
D. public class Generator implements IdGenerator (
Private volatile int Id -0;
Public int getNExt Td() |
Synchronized (new generator()) {
return ++id;
}
}
}
E. public Class Generator implement IdGenerator (
Private int id =0;
Public int getNextId { ) {
Synchronized (id) ;
return ++id
}
}
Answer: C

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