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NEW QUESTION: 1
A media company produces new video files on-premises every day with a total size of around 100GBS after compression All files have a size of 1 -2 GB and need to be uploaded to Amazon S3 every night in a fixed time window between 3am and 5am Current upload takes almost 3 hours, although less than half of the available bandwidth is used.
What step(s) would ensure that the file uploads are able to complete in the allotted time window?
A. Upload the files in parallel to S3
B. Pack all files into a single archive, upload it to S3, then extract the files in AWS
C. Use AWS Import/Export to transfer the video files
D. Increase your network bandwidth to provide faster throughput to S3
Answer: A
Explanation:
Reference:
http://aws.amazon.com/importexport/faqs/

NEW QUESTION: 2
What is the result of executing a TRUNCATE TABLE command on a table that has Flashback Archiving enabled?
A. The rows in both the table and the archive are truncated.
B. The rows in the table are archived, and then truncated.
C. It fails with the ORA-665610 Invalid DDL statement on history-tracked message
D. The rows in the table are truncated without being archived.
Answer: B
Explanation:
http://surachartopun.com/2010/06/ddl-on-tables-enabled-for-flashback.html

NEW QUESTION: 3
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?
A. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>'' ANDSUBSTR (cust_first_name, -2, 1)='a';
B. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR (cust_first_name, -2, 1)='a';
C. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR (cust_first_name, LENGTH(cust_first_name),-2)='a';
D. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')IS NOT NULL ANDSUBSTR(cust_first_name, 1,-2)='a';
Answer: B
Explanation:
Explanation/Reference:
Explanation:
The SUBSTR(string, start position, number of characters) function accepts three parameters and returns a string consisting of the number of characters extracted from the source string, beginning at the specified start position:
substr('http://www.domain.com',12,6) = domain
The position at which the first character of the returned string begins.
When position is 0 (zero), then it is treated as 1.
When position is positive, then the function counts from the beginning of string to find the first character.
When position is negative, then the function counts backward from the end of string.
substring_length
The length of the returned string. SUBSTR calculates lengths using characters as defined by the input character set. SUBSTRB uses bytes instead of characters. SUBSTRC uses Unicode complete characters.
SUBSTR2 uses UCS2 code points. SUBSTR4 uses UCS4 code points.
When you do not specify a value for this argument, then the function
The INSTR(source string, search item, [start position],[nth occurrence of search item]) function returns a number that represents the position in the source string, beginning from the given start position, where the nth occurrence of the search item begins:
instr('http://www.domain.com','.',1,2) = 18

NEW QUESTION: 4


Answer:
Explanation:

Explanation

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